Rewrite the following equation in slope-intercept form. 16x + 12y = 13 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y: Isolate y in the equation. We start by moving the term involving x to the other side of the equation: 12y = -16x + 13Divide for y: Divide all terms by the coefficient of y to solve for y. Divide each term by 12 to isolate y: y = (-16/12)x + 13/12Simplify fractions: Simplify the fractions. Simplify -16/12 to -4/3 and 13/12 remains as it is because it cannot be simplified further: y = (-4/3)x + 13/12

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Rewrite the following equation in slope-intercept form. $\newline$ $16x + 12y = 13$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

\newline

16x + 12y = 13

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y: Isolate $y$ in the equation. $\newline$ We start by moving the term involving $x$ to the other side of the equation: $\newline$ $12y = -16x + 13$
Divide for $y$ : Divide all terms by the coefficient of $y$ to solve for $y$ . $\newline$ Divide each term by $12$ to isolate $y$ : $\newline$ $y = \frac{-16}{12}x + \frac{13}{12}$
Simplify fractions: Simplify the fractions. $\newline$ Simplify $-\frac{16}{12}$ to $-\frac{4}{3}$ and $\frac{13}{12}$ remains as it is because it cannot be simplified further: $\newline$ $y = \left(-\frac{4}{3}\right)x + \frac{13}{12}$