Rewrite the following equation in slope-intercept form. 6x + 19y = –13 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y-term: Step 1: Isolate the y-term on one side of the equation. We start by subtracting 6x from both sides of the equation 6x + 19y = –13. This gives us 19y = -6x - 13.Solve for y: Step 2: Solve for y by dividing all terms by the coefficient of y, which is 19. Dividing each term by 19, we get y = (-6/19)x - 13/19.

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Rewrite the following equation in slope-intercept form. $\newline$ $6x + 19y = -13$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

\newline

6x + 19y = -13

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y-term: Step $1$ : Isolate the y-term on one side of the equation. $\newline$ We start by subtracting $6x$ from both sides of the equation $6x + 19y = -13$ . $\newline$ This gives us $19y = -6x - 13$ .
Solve for y: Step $2$ : Solve for y by dividing all terms by the coefficient of y, which is $19$ . Dividing each term by $19$ , we get $y = \frac{-6}{19}x - \frac{13}{19}$ .