Rewrite the following equation in slope-intercept form. 7x − 3y = 5 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y-term: Step 1: Isolate the y-term on one side of the equation. We start by moving the 7x to the other side of the equation by subtracting 7x from both sides. Calculation: 7x - 3y = 5 becomes -3y = -7x + 5.Solve for y: Step 2: Solve for y by dividing all terms by -3. To get y by itself, we divide every term by -3. Calculation: y = (-7x + 5) / -3. Simplifying further, y = (7/3)x - 5/3.

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Rewrite the following equation in slope-intercept form. $\newline$ $7x - 3y = 5$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

\newline

7x - 3y = 5

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y-term: Step $1$ : Isolate the $y$ -term on one side of the equation. $\newline$ We start by moving the $7x$ to the other side of the equation by subtracting $7x$ from both sides. $\newline$ Calculation: $7x - 3y = 5$ becomes $-3y = -7x + 5$ .
Solve for y: Step $2$ : Solve for y by dividing all terms by $-3$ . $\newline$ To get $y$ by itself, we divide every term by $-3$ . $\newline$ Calculation: $y = (-7x + 5) / -3$ . $\newline$ Simplifying further, $y = (7/3)x - 5/3$ .