Rewrite the following equation in slope-intercept form. 19x + 20y = 6 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y: Step 1: Isolate y in the equation. To rewrite the equation in slope-intercept form (y = mx + b), we need to solve for y. Start by subtracting 19x from both sides of the equation: 20y = -19x + 6 Divide for y: Step 2: Divide all terms by 20 to solve for y. Divide each term by 20 to isolate y: y = (-19x + 6) / 20 This simplifies to: y = -19/20x + 6/20 Simplify constant term: Step 3: Simplify the constant term. Simplify 6/20 to its lowest terms: 6/20 = 3/10

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Rewrite the following equation in slope-intercept form. $\newline$ $19x + 20y = 6$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

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19x + 20y = 6

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Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y: Step $1$ : Isolate y in the equation. $\newline$ To rewrite the equation in slope-intercept form $y = mx + b$ , we need to solve for y. $\newline$ Start by subtracting $19x$ from both sides of the equation: $\newline$ $20y = -19x + 6$
Divide for y: Step $2$ : Divide all terms by $20$ to solve for $y$ . $\newline$ Divide each term by $20$ to isolate $y$ : $\newline$ $y = (-19x + 6) / 20$ $\newline$ This simplifies to: $\newline$ $y = -\frac{19}{20}x + \frac{6}{20}$
Simplify constant term: Step $3$ : Simplify the constant term. $\newline$ Simplify $\frac{6}{20}$ to its lowest terms: $\newline$ $\frac{6}{20} = \frac{3}{10}$