Rewrite the following equation in slope-intercept form. 8x + 3y = –18 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y-term: Step 1: Isolate the y-term on one side of the equation. To rewrite the equation 8x + 3y = –18 in slope-intercept form (y = mx + b), we start by moving the x-term to the other side. Subtract 8x from both sides: 3y = -8x - 18 Solve for y: Step 2: Solve for y by dividing all terms by the coefficient of y. Divide every term by 3 to isolate y: y = (-8/3)x - 6

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Rewrite the following equation in slope-intercept form. $\newline$ $8x + 3y = -18$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

\newline

8x + 3y = -18

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y-term: Step $1$ : Isolate the $y$ -term on one side of the equation. $\newline$ To rewrite the equation $8x + 3y = -18$ in slope-intercept form ( $y = mx + b$ ), we start by moving the $x$ -term to the other side. Subtract $8x$ from both sides: $\newline$ $3y = -8x - 18$
Solve for y: Step $2$ : Solve for y by dividing all terms by the coefficient of y. $\newline$ Divide every term by $3$ to isolate y: $\newline$ $y = \frac{-8}{3}x - 6$