Rewrite the following equation in slope-intercept form. 14x − 7y = –3 Write your answer using integers, proper fractions, and improper fractions in simplest form. _____

Isolate y-term: Step 1: Isolate the y-term on one side of the equation. We start by moving the 14x to the other side of the equation by subtracting 14x from both sides. 14x - 7y = -3 becomes -7y = -14x - 3. Solve for y: Step 2: Solve for y by dividing all terms by -7. To get y by itself, divide every term by -7. -7y / -7 = (-14x - 3) / -7. This simplifies to y = 2x + 3/7.

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Rewrite the following equation in slope-intercept form. $\newline$ $14x - 7y = -3$ $\newline$ Write your answer using integers, proper fractions, and improper fractions in simplest form. $\newline$ $\_\_$

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Grade 8

Convert a linear equation in standard form to slope-intercept form

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Q. Rewrite the following equation in slope-intercept form.

\newline

14x - 7y = -3

\newline

Write your answer using integers, proper fractions, and improper fractions in simplest form.

\newline

\_\_

Isolate y-term: Step $1$ : Isolate the $y$ -term on one side of the equation. $\newline$ We start by moving the $14x$ to the other side of the equation by subtracting $14x$ from both sides. $\newline$ $14x - 7y = -3$ becomes $-7y = -14x - 3$ .
Solve for y: Step $2$ : Solve for y by dividing all terms by $-7$ . $\newline$ To get $y$ by itself, divide every term by $-7$ . $\newline$ $-7y / -7 = (-14x - 3) / -7$ . $\newline$ This simplifies to $y = 2x + \frac{3}{7}$ .