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Rewrite the expression as a product of four linear factors:

(x^(2)-5x)^(2)-2(x^(2)-5x)-24
Answer:

Rewrite the expression as a product of four linear factors:\newline(x25x)22(x25x)24 \left(x^{2}-5 x\right)^{2}-2\left(x^{2}-5 x\right)-24 \newlineAnswer:

Full solution

Q. Rewrite the expression as a product of four linear factors:\newline(x25x)22(x25x)24 \left(x^{2}-5 x\right)^{2}-2\left(x^{2}-5 x\right)-24 \newlineAnswer:
  1. Identify Expression: Let's identify the expression we need to factor: (x25x)22(x25x)24(x^2 - 5x)^2 - 2(x^2 - 5x) - 24. To simplify the factoring process, let's use a substitution where u=x25xu = x^2 - 5x. This will allow us to rewrite the expression in terms of uu, which will look like a quadratic equation.\newlineSubstitute uu for (x25x)(x^2 - 5x): u22u24u^2 - 2u - 24.
  2. Substitute and Simplify: Now we have a quadratic equation in terms of uu: u22u24u^2 - 2u - 24. We need to factor this quadratic equation.\newlineTo factor u22u24u^2 - 2u - 24, we look for two numbers that multiply to 24-24 and add up to 2-2. These numbers are 6-6 and +4+4.\newlineSo, we can write u22u24u^2 - 2u - 24 as (u6)(u+4)(u - 6)(u + 4).
  3. Factor Quadratic Equation: Now that we have factored the quadratic in terms of uu, we need to substitute back x25xx^2 - 5x for uu to get the expression in terms of xx. Substitute back: (u6)(u+4)(u - 6)(u + 4) becomes ((x25x)6)((x25x)+4)((x^2 - 5x) - 6)((x^2 - 5x) + 4).
  4. Substitute Back: We now have two quadratic factors: ((x25x)6)((x^2 - 5x) - 6) and ((x25x)+4)((x^2 - 5x) + 4). Each of these can be factored further into linear factors.\newlineFirst, let's factor (x25x6)(x^2 - 5x - 6). We look for two numbers that multiply to 6-6 and add up to 5-5. These numbers are 6-6 and +1+1.\newlineSo, we can write x25x6x^2 - 5x - 6 as (x6)(x+1)(x - 6)(x + 1).
  5. Factor Quadratic Factors: Next, we factor (x25x+4)(x^2 - 5x + 4). We look for two numbers that multiply to 44 and add up to 5-5. These numbers are 4-4 and 1-1. So, we can write x25x+4x^2 - 5x + 4 as (x4)(x1)(x - 4)(x - 1).
  6. Factor Linear Factors: Now we have all four linear factors: (x6)(x - 6), (x+1)(x + 1), (x4)(x - 4), and (x1)(x - 1). The original expression (x25x)22(x25x)24(x^2 - 5x)^2 - 2(x^2 - 5x) - 24 can be rewritten as the product of these four linear factors. The final expression is: (x6)(x+1)(x4)(x1)(x - 6)(x + 1)(x - 4)(x - 1).

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