Rewrite the expression as a product of four linear factors: (x^(2)+4x)^(2)-9(x^(2)+4x)-36 Answer:

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Rewrite the expression as a product of four linear factors:  (x^(2)+4x)^(2)-9(x^(2)+4x)-36 Answer:

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Identify Expression: Let's first identify the expression we need to factor: (x^2 + 4x)^2 - 9(x^2 + 4x) - 36. This expression resembles a quadratic in form, where (x^2 + 4x) is our ＂variable＂. Let's substitute y = x^2 + 4x to make it look more like a standard quadratic equation.Substitute y: Substitute y into the expression to get: y^2 - 9y - 36. Now we have a quadratic equation in terms of y, which we can factor.Factor Quadratic Equation: Factor the quadratic equation y^2 - 9y - 36. We are looking for two numbers that multiply to -36 and add up to -9. These numbers are -12 and +3. So, the factored form is (y - 12)(y + 3).Substitute x^2 + 4x: Now we need to substitute x^2 + 4x back in for y to get: (x^2 + 4x - 12)(x^2 + 4x + 3).Factor x^2 + 4x - 12: Next, we need to factor each of these quadratic expressions further. Starting with x^2 + 4x - 12, we look for two numbers that multiply to -12 and add up to 4. These numbers are 6 and -2. So, the factored form is (x + 6)(x - 2).Factor x^2 + 4x + 3: Now, factor x^2 + 4x + 3. We look for two numbers that multiply to 3 and add up to 4. These numbers are 3 and 1. So, the factored form is (x + 3)(x + 1).Combine Linear Factors: Finally, we combine all the linear factors to express the original expression as a product of four linear factors: (x + 6)(x - 2)(x + 3)(x + 1).

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}+4 x\right)^{2}-9\left(x^{2}+4 x\right)-36$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(x2+4x)2−9(x2+4x)−36 \left(x^{2}+4 x\right)^{2}-9\left(x^{2}+4 x\right)-36 (x2+4x)2−9(x2+4x)−36\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}+4 x\right)^{2}-9\left(x^{2}+4 x\right)-36$ $\newline$ Answer: