Rewrite the expression as a product of four linear factors: (12x^(2)-19 x)^(2)-5(12x^(2)-19 x)-50 Answer:

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Rewrite the expression as a product of four linear factors:  (12x^(2)-19 x)^(2)-5(12x^(2)-19 x)-50 Answer:

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Denote expression as y: Let's denote the expression inside the parentheses as y, so we have: y = 12x^2 - 19x Now the given expression can be rewritten as: y^2 - 5y - 50 We will factor this quadratic expression in terms of y.Factor quadratic expression: To factor y^2 - 5y - 50, we need to find two numbers that multiply to -50 and add up to -5. These numbers are -10 and 5. So we can write the quadratic as: (y - 10)(y + 5)Substitute back and simplify: Now we substitute back 12x^2 - 19x for y to get the expression in terms of x: (12x^2 - 19x - 10)(12x^2 - 19x + 5)Factor first quadratic expression: Next, we need to factor each quadratic expression. We start with 12x^2 - 19x - 10. We look for two numbers that multiply to 12 * -10 = -120 and add up to -19. These numbers are -20 and 6. So we can write the quadratic as: (4x - 10)(3x + 1)Factor second quadratic expression: Now we factor the second quadratic expression, 12x^2 - 19x + 5. We look for two numbers that multiply to 12 * 5 = 60 and add up to -19. These numbers are -15 and -4. So we can write the quadratic as: (3x - 5)(4x - 1)Write original expression as product: Finally, we write the original expression as a product of four linear factors: (4x - 10)(3x + 1)(3x - 5)(4x - 1)

Rewrite the expression as a product of four linear factors: $\newline$ $\left(12 x^{2}-19 x\right)^{2}-5\left(12 x^{2}-19 x\right)-50$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(12x2−19x)2−5(12x2−19x)−50 \left(12 x^{2}-19 x\right)^{2}-5\left(12 x^{2}-19 x\right)-50 (12x2−19x)2−5(12x2−19x)−50\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(12 x^{2}-19 x\right)^{2}-5\left(12 x^{2}-19 x\right)-50$ $\newline$ Answer: