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Re-write the quadratic function below in Standard Form

y=-9(x-1)(x+9)
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=9(x1)(x+9) y=-9(x-1)(x+9) \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=9(x1)(x+9) y=-9(x-1)(x+9) \newlineAnswer: y= y=
  1. Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as the FOIL method for binomials).\newlineWe need to multiply each term in the first binomial by each term in the second binomial.\newliney=9(x1)(x+9)y = -9(x - 1)(x + 9)\newliney=9[(x)(x)+(x)(9)(1)(x)(1)(9)]y = -9[(x)(x) + (x)(9) - (1)(x) - (1)(9)]
  2. Perform Multiplication: Perform the multiplication for each pair of terms.\newliney=9[x2+9xx9]y = -9[x^2 + 9x - x - 9]
  3. Combine Like Terms: Combine like terms inside the brackets.\newliney=9[x2+8x9]y = -9[x^2 + 8x - 9]
  4. Distribute 9-9: Distribute the 9-9 to each term inside the brackets.\newliney=9(x2)9(8x)+9(9)y = -9(x^2) - 9(8x) + 9(9)
  5. Perform Multiplication: Perform the multiplication.\newliney=9x272x+81y = -9x^2 - 72x + 81

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