Re-write the quadratic function below in Standard Form y=-8(x+4)(x+1) Answer: y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as FOIL - First, Outer, Inner, Last). We have y = -8(x + 4)(x + 1). First, we'll multiply the terms inside the parentheses. y = -8[(x)(x) + (x)(1) + (4)(x) + (4)(1)]Combine Like Terms: Continue the expansion by combining like terms. y = -8(x^2 + x + 4x + 4) y = -8(x^2 + 5x + 4)Distribute -8: Distribute the -8 across each term inside the parentheses. y = -8(x^2) - 8(5x) - 8(4) y = -8x^2 - 40x - 32Standard Form Expression: Write the final expression in Standard Form, which is Ax^2 + Bx + C. y = -8x^2 - 40x - 32 This is the Standard Form of the quadratic function.

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Re-write the quadratic function below in Standard Form

y=-8(x+4)(x+1)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-8(x+4)(x+1)$ $\newline$ Answer: $y=$

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-8(x+4)(x+1)

\newline

Answer:

y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as FOIL - First, Outer, Inner, Last). We have $y = -8(x + 4)(x + 1)$ . First, we'll multiply the terms inside the parentheses. $y = -8[(x)(x) + (x)(1) + (4)(x) + (4)(1)]$
Combine Like Terms: Continue the expansion by combining like terms. $\newline$ $y = -8(x^2 + x + 4x + 4)$ $\newline$ $y = -8(x^2 + 5x + 4)$
Distribute $-8$ : Distribute the $-8$ across each term inside the parentheses. $\newline$ $y = -8(x^2) - 8(5x) - 8(4)$ $\newline$ $y = -8x^2 - 40x - 32$
Standard Form Expression: Write the final expression in Standard Form, which is $Ax^2 + Bx + C$ . $\newline$ $y = -8x^2 - 40x - 32$ $\newline$ This is the Standard Form of the quadratic function.