Re-write the quadratic function below in Standard Form y=-7(x-3)^(2)+4 Answer: y=

Multiply by -7: Now we multiply each term inside the parentheses by -7. y = -7(x²) - 7(-6x) - 7(9) + 4 = -7x² + 42x - 63 + 4Combine constant terms: Finally, we combine the constant terms. y = -7x² + 42x - 63 + 4 y = -7x² + 42x - 59 This is the quadratic function in Standard Form.

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Re-write the quadratic function below in Standard Form

y=-7(x-3)^(2)+4
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-7(x-3)^{2}+4$ $\newline$ Answer: $y=$

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Algebra 2

Quadratic equation with complex roots

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-7(x-3)^{2}+4

\newline

Answer:

y=

Multiply by $-7$ : Now we multiply each term inside the parentheses by $-7$ . $\newline$ $y = -7(x^2) - 7(-6x) - 7(9) + 4$ $\newline$ $= -7x^2 + 42x - 63 + 4$
Combine constant terms: Finally, we combine the constant terms. $\newline$ $y = -7x^2 + 42x - 63 + 4$ $\newline$ $y = -7x^2 + 42x - 59$ $\newline$ This is the quadratic function in Standard Form.