Re-write the quadratic function below in Standard Form y=7(x-2)^(2)+2 Answer: y=

Expand Squared Term: Expand the squared term (x-2)². (x-2)² = (x-2)(x-2) = x² - 4x + 4Multiply by Coefficient: Multiply the expanded term by the coefficient 7. 7(x² - 4x + 4) = 7x² - 28x + 28Add Constant Term: Add the constant term 2 to the expression. 7x² - 28x + 28 + 2 = 7x² - 28x + 30Write in Standard Form: Write the final expression in standard form. y = 7x² - 28x + 30

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Re-write the quadratic function below in Standard Form

y=7(x-2)^(2)+2
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=7(x-2)^{2}+2$ $\newline$ Answer: $y=$

View step-by-step help

Home

Math Problems

Algebra 2

Quadratic equation with complex roots

Full solution

Q. Re-write the quadratic function below in Standard Form

\newline

y=7(x-2)^{2}+2

\newline

Answer:

y=

Expand Squared Term: Expand the squared term $(x-2)^2$ . $(x-2)^2 = (x-2)(x-2) = x^2 - 4x + 4$
Multiply by Coefficient: Multiply the expanded term by the coefficient $7$ . $7(x^2 - 4x + 4) = 7x^2 - 28x + 28$
Add Constant Term: Add the constant term $2$ to the expression. $7x^2 - 28x + 28 + 2 = 7x^2 - 28x + 30$
Write in Standard Form: Write the final expression in standard form. $\newline$ $y = 7x^2 - 28x + 30$