Re-write the quadratic function below in Standard Form y=-7(x+1)^(2)+6 Answer: y=

Expand and Distribute: To rewrite the quadratic function in Standard Form, we need to expand the squared term and distribute the -7 across the terms inside the parentheses. y = -7(x + 1)² + 6 y = -7(x² + 2x + 1) + 6Distribute -7: Now, distribute the -7 to each term inside the parentheses. y = -7 * x² - 7 * 2x - 7 * 1 + 6 y = -7x² - 14x - 7 + 6Combine Constant Terms: Combine the constant terms to simplify the equation. y = -7x² - 14x - 1Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is y = ax² + bx + c.

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Re-write the quadratic function below in Standard Form

y=-7(x+1)^(2)+6
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-7(x+1)^{2}+6$ $\newline$ Answer: $y=$

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Quadratic equation with complex roots

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-7(x+1)^{2}+6

\newline

Answer:

y=

Expand and Distribute: To rewrite the quadratic function in Standard Form, we need to expand the squared term and distribute the $-7$ across the terms inside the parentheses. $\newline$ $y = -7(x + 1)^2 + 6$ $\newline$ $y = -7(x^2 + 2x + 1) + 6$
Distribute $-7$ : Now, distribute the $-7$ to each term inside the parentheses. $\newline$ $y = -7 \times x^2 - 7 \times 2x - 7 \times 1 + 6$ $\newline$ $y = -7x^2 - 14x - 7 + 6$
Combine Constant Terms: Combine the constant terms to simplify the equation. $\newline$ $y = -7x^2 - 14x - 1$
Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is $y = ax^2 + bx + c$ .