Re-write the quadratic function below in Standard Form y=-6(x-1)^(2)-6 Answer: y=

Expand squared term: To rewrite the quadratic function in Standard Form, we need to expand the squared term and simplify the expression. The Standard Form of a quadratic function is y = ax^2 + bx + c.Multiply by -6: First, expand the squared term (x - 1)². (x - 1)² = (x - 1)(x - 1) = x² - 2x + 1Add constant term: Now, multiply the expanded term by -6. -6(x² - 2x + 1) = -6x² + 12x - 6Combine constant terms: Finally, add the constant term -6 to the expression. y = -6x² + 12x - 6 - 6Combine the constant terms to simplify the expression. y = -6x² + 12x - 12

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Re-write the quadratic function below in Standard Form

y=-6(x-1)^(2)-6
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-6(x-1)^{2}-6$ $\newline$ Answer: $y=$

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-6(x-1)^{2}-6

\newline

Answer:

y=

Expand squared term: To rewrite the quadratic function in Standard Form, we need to expand the squared term and simplify the expression. $\newline$ The Standard Form of a quadratic function is $y = ax^2 + bx + c$ .
Multiply by $-6$ : First, expand the squared term $(x - 1)^2$ . $(x - 1)^2 = (x - 1)(x - 1) = x^2 - 2x + 1$
Add constant term: Now, multiply the expanded term by \(-6＂). $\newline$ \(-6(x^ $2$ - $2$ x + $1$ ) = $-6$ x^ $2$ + $12$ x - $6$ ＂}
Combine constant terms: Finally, add the constant term $-6$ to the expression. $y = -6x^2 + 12x - 6 - 6$
Combine constant terms: Finally, add the constant term $-6$ to the expression. $\newline$ y = $-6x^2 + 12x - 6 - 6$ Combine the constant terms to simplify the expression. $\newline$ y = $-6x^2 + 12x - 12$