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Re-write the quadratic function below in Standard Form

y=-5(x-2)^(2)+3
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=5(x2)2+3 y=-5(x-2)^{2}+3 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=5(x2)2+3 y=-5(x-2)^{2}+3 \newlineAnswer: y= y=
  1. Expand Squared Term: Expand the squared term (x2)2(x - 2)^2.\newlineReasoning: To write the quadratic function in Standard Form, we need to expand the squared term and then distribute the coefficient 5-5.\newlineCalculation: (x2)2=x24x+4(x - 2)^2 = x^2 - 4x + 4
  2. Distribute Coefficient: Distribute the coefficient 5-5 to the expanded terms.\newlineReasoning: Multiplying each term in the expansion by 5-5 will give us the quadratic in an expanded form.\newlineCalculation: 5(x24x+4)=5x2+20x20-5(x^2 - 4x + 4) = -5x^2 + 20x - 20
  3. Add Constant Term: Add the constant term +3+3 to the result from Step 22.\newlineReasoning: To complete the quadratic function, we add the constant term to the expression obtained after distribution.\newlineCalculation: 5x2+20x20+3=5x2+20x17-5x^2 + 20x - 20 + 3 = -5x^2 + 20x - 17
  4. Write Final Function: Write the final quadratic function in Standard Form.\newlineReasoning: The Standard Form of a quadratic function is ax2+bx+cax^2 + bx + c. We have all the terms from the previous steps to write the function in this form.\newlineCalculation: y=5x2+20x17y = -5x^2 + 20x - 17

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