Re-write the quadratic function below in Standard Form y=4(x+1)(x-5) Answer: y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as the FOIL method for binomials). We need to multiply the two binomials (x+1) and (x-5) together. y = 4(x+1)(x-5) y = 4[(x)(x) + (x)(-5) + (1)(x) + (1)(-5)]Combine Like Terms: Continue expanding the expression by combining like terms. y = 4[x^2 - 5x + x - 5] y = 4[x^2 - 4x - 5]Distribute Coefficient: Distribute the 4 across each term inside the brackets. y = 4x^2 - 16x - 20Check Standard Form: Check that the quadratic is in Standard Form. The Standard Form of a quadratic function is y = ax^2 + bx + c. Our function is now in the form y = 4x^2 - 16x - 20, which matches the Standard Form.

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Re-write the quadratic function below in Standard Form

y=4(x+1)(x-5)
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=4(x+1)(x-5)$ $\newline$ Answer: $y=$

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Algebra 1

Multiply two binomials

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Q. Re-write the quadratic function below in Standard Form

\newline

y=4(x+1)(x-5)

\newline

Answer:

y=

Expand Quadratic Function: Expand the quadratic function using the distributive property (also known as the FOIL method for binomials). $\newline$ We need to multiply the two binomials $(x+1)$ and $(x-5)$ together. $\newline$ $y = 4(x+1)(x-5)$ $\newline$ $y = 4[(x)(x) + (x)(-5) + (1)(x) + (1)(-5)]$
Combine Like Terms: Continue expanding the expression by combining like terms. $\newline$ $y = 4[x^2 - 5x + x - 5]$ $\newline$ $y = 4[x^2 - 4x - 5]$
Distribute Coefficient: Distribute the $4$ across each term inside the brackets. $\newline$ $y = 4x^2 - 16x - 20$
Check Standard Form: Check that the quadratic is in Standard Form. $\newline$ The Standard Form of a quadratic function is $y = ax^2 + bx + c$ . Our function is now in the form $y = 4x^2 - 16x - 20$ , which matches the Standard Form.