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Re-write the quadratic function below in Standard Form

y=4(x+3)^(2)+6
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=4(x+3)2+6 y=4(x+3)^{2}+6 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=4(x+3)2+6 y=4(x+3)^{2}+6 \newlineAnswer: y= y=
  1. Expand Squared Term: Expand the squared term (x+3)2(x+3)^2.\newlineReasoning: To write the quadratic function in standard form, we need to expand the squared term and simplify.\newlineCalculation: (x+3)2=x2+2(x3)+32=x2+6x+9(x+3)^2 = x^2 + 2\cdot(x\cdot3) + 3^2 = x^2 + 6x + 9
  2. Multiply by Coefficient: Multiply the expanded term by the coefficient 44.\newlineReasoning: The original function has a coefficient of 44 that needs to be distributed to each term in the expanded squared term.\newlineCalculation: 4(x2+6x+9)=4x2+24x+364*(x^2 + 6x + 9) = 4x^2 + 24x + 36
  3. Add Constant Term: Add the constant term 66 to the result from Step 22.\newlineReasoning: The constant term 66 needs to be included to complete the standard form of the quadratic function.\newlineCalculation: 4x2+24x+36+6=4x2+24x+424x^2 + 24x + 36 + 6 = 4x^2 + 24x + 42
  4. Write Final Function: Write the final standard form of the quadratic function.\newlineReasoning: After expanding, multiplying, and adding the constant term, we have the quadratic function in standard form.\newlineCalculation: y=4x2+24x+42y = 4x^2 + 24x + 42

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