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Re-write the quadratic function below in Standard Form

y=4(x-4)^(2)-7
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=4(x4)27 y=4(x-4)^{2}-7 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=4(x4)27 y=4(x-4)^{2}-7 \newlineAnswer: y= y=
  1. Expand Squared Term: Expand the squared term (x4)2(x-4)^2.\newlineReasoning: To write the quadratic function in Standard Form, we need to expand the squared term and simplify.\newlineCalculation: (x4)2=x22×(4)×x+42=x28x+16(x-4)^2 = x^2 - 2\times(4)\times x + 4^2 = x^2 - 8x + 16
  2. Multiply by Coefficient: Multiply the expanded term by the coefficient 44. Reasoning: The quadratic function has a coefficient of 44 that needs to be distributed to each term in the expanded squared term. Calculation: 4(x28x+16)=4x232x+644*(x^2 - 8x + 16) = 4x^2 - 32x + 64
  3. Subtract Constant: Subtract 77 from the result of Step 22.\newlineReasoning: The quadratic function includes a constant term 7-7 that needs to be combined with the result from Step 22 to complete the Standard Form.\newlineCalculation: 4x232x+647=4x232x+574x^2 - 32x + 64 - 7 = 4x^2 - 32x + 57
  4. Write Standard Form: Write the final Standard Form of the quadratic function.\newlineReasoning: After expanding, distributing, and combining like terms, we have the quadratic function in Standard Form.\newlineCalculation: y=4x232x+57y = 4x^2 - 32x + 57

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