Re-write the quadratic function below in Standard Form y=-3(x-2)^(2)-8 Answer: y=

Apply Distributive Property: Now, we multiply the expanded form by -3 to apply the distributive property. y = -3(x² - 4x + 4) - 8 y = -3x² + 12x - 12 - 8Combine Constant Terms: Next, we combine the constant terms -12 and -8 to simplify the expression further. y = -3x² + 12x - 20Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is y = ax² + bx + c.

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Re-write the quadratic function below in Standard Form

y=-3(x-2)^(2)-8
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-3(x-2)^{2}-8$ $\newline$ Answer: $y=$

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Algebra 2

Quadratic equation with complex roots

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Q. Re-write the quadratic function below in Standard Form

\newline

y=-3(x-2)^{2}-8

\newline

Answer:

y=

Apply Distributive Property: Now, we multiply the expanded form by $-3$ to apply the distributive property. $\newline$ y = $-3(x^2 - 4x + 4) - 8$ $\newline$ y = $-3x^2 + 12x - 12 - 8$
Combine Constant Terms: Next, we combine the constant terms $-12$ and $-8$ to simplify the expression further. $y = -3x^2 + 12x - 20$
Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is $y = ax^2 + bx + c$ .