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Re-write the quadratic function below in Standard Form

y=3(x+5)^(2)-1
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=3(x+5)21 y=3(x+5)^{2}-1 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=3(x+5)21 y=3(x+5)^{2}-1 \newlineAnswer: y= y=
  1. Expand Squared Term: Expand the squared term (x+5)2(x+5)^2.\newlineReasoning: To write the quadratic function in standard form, we need to expand the squared term and simplify.\newlineCalculation: (x+5)2=x2+2(5)x+52=x2+10x+25(x+5)^2 = x^2 + 2\cdot(5)\cdot x + 5^2 = x^2 + 10x + 25
  2. Multiply by Coefficient: Multiply the expanded term by the coefficient 33.\newlineReasoning: The quadratic function has a coefficient of 33 that needs to be distributed to each term in the expansion.\newlineCalculation: 3(x2+10x+25)=3x2+310x+325=3x2+30x+753*(x^2 + 10x + 25) = 3x^2 + 3*10x + 3*25 = 3x^2 + 30x + 75
  3. Subtract from Result: Subtract 11 from the result.\newlineReasoning: The quadratic function has a constant term 1-1 that needs to be included in the standard form.\newlineCalculation: 3x2+30x+751=3x2+30x+743x^2 + 30x + 75 - 1 = 3x^2 + 30x + 74
  4. Write Final Standard Form: Write the final standard form of the quadratic function.\newlineReasoning: After expanding, multiplying, and subtracting, we have the standard form of the quadratic function.\newlineCalculation: y=3x2+30x+74y = 3x^2 + 30x + 74

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