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Re-write the quadratic function below in Standard Form

y=3(x+1)^(2)-4
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=3(x+1)24 y=3(x+1)^{2}-4 \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=3(x+1)24 y=3(x+1)^{2}-4 \newlineAnswer: y= y=
  1. Expand and Distribute: To rewrite the quadratic function in standard form, we need to expand the squared term and distribute the coefficient 33 through the parentheses.y=3(x+1)24y = 3(x+1)^2 - 4y=3(x2+2x+1)4y = 3(x^2 + 2x + 1) - 4
  2. Distribute Coefficient: Now we distribute the 33 to each term inside the parentheses.\newliney=3x2+6x+34y = 3x^2 + 6x + 3 - 4
  3. Combine Constant Terms: Combine the constant terms 33 and 4-4 to simplify the equation.y=3x2+6x1y = 3x^2 + 6x - 1

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