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Re-write the quadratic function below in Standard Form

y=2(x+9)(x-5)
Answer: 
y=

Re-write the quadratic function below in Standard Form\newliney=2(x+9)(x5) y=2(x+9)(x-5) \newlineAnswer: y= y=

Full solution

Q. Re-write the quadratic function below in Standard Form\newliney=2(x+9)(x5) y=2(x+9)(x-5) \newlineAnswer: y= y=
  1. Combine like terms: Now, we will simplify the expression by combining like terms.\newliney=2(x25x+9x45)y = 2(x^2 - 5x + 9x - 45)\newliney=2(x2+4x45)y = 2(x^2 + 4x - 45)
  2. Distribute the 22: Next, we distribute the 22 across each term inside the parentheses.\newliney=2(x2)+2(4x)2(45)y = 2(x^2) + 2(4x) - 2(45)\newliney=2x2+8x90y = 2x^2 + 8x - 90
  3. Standard form: The quadratic function is now in standard form, which is y=ax2+bx+cy = ax^2 + bx + c.\newlineTherefore, the standard form of the given quadratic function is y=2x2+8x90y = 2x^2 + 8x - 90.

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