Re-write the quadratic function below in Standard Form y=-2(x-5)^(2)+6 Answer: y=

Expand and Distribute: To rewrite the quadratic function in Standard Form, we need to expand the squared term and distribute the -2 across the terms inside the parentheses. y = -2(x - 5)² + 6 y = -2(x² - 10x + 25) + 6Distribute -2: Now, distribute the -2 to each term inside the parentheses. y = -2 * x² + 2 * 10x - 2 * 25 + 6 y = -2x² + 20x - 50 + 6Combine Constant Terms: Combine the constant terms to simplify the equation. y = -2x² + 20x - 44Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is y = ax² + bx + c.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Re-write the quadratic function below in Standard Form

y=-2(x-5)^(2)+6
Answer:
y=

Re-write the quadratic function below in Standard Form $\newline$ $y=-2(x-5)^{2}+6$ $\newline$ Answer: $y=$

View step-by-step help

Home

Math Problems

Algebra 2

Quadratic equation with complex roots

Full solution

Q. Re-write the quadratic function below in Standard Form

\newline

y=-2(x-5)^{2}+6

\newline

Answer:

y=

Expand and Distribute: To rewrite the quadratic function in Standard Form, we need to expand the squared term and distribute the $-2$ across the terms inside the parentheses. $\newline$ $y = -2(x - 5)^2 + 6$ $\newline$ $y = -2(x^2 - 10x + 25) + 6$
Distribute $-2$ : Now, distribute the $-2$ to each term inside the parentheses. $\newline$ $y = -2 \times x^2 + 2 \times 10x - 2 \times 25 + 6$ $\newline$ $y = -2x^2 + 20x - 50 + 6$
Combine Constant Terms: Combine the constant terms to simplify the equation. $\newline$ $y = -2x^2 + 20x - 44$
Quadratic Function in Standard Form: The quadratic function is now in Standard Form, which is $y = ax^2 + bx + c$ .