Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:


A new car is purchased for 15300 dollars. The value of the car depreciates at 
14.25% per year. What will the value of the car be, to the nearest cent, after 6 years?

A new car is purchased for 1530015300 dollars. The value of the car depreciates at 14.25% 14.25 \% per year. What will the value of the car be, to the nearest cent, after 66 years?

Full solution

Q. A new car is purchased for 1530015300 dollars. The value of the car depreciates at 14.25% 14.25 \% per year. What will the value of the car be, to the nearest cent, after 66 years?
  1. Calculate Depreciation: To calculate the depreciation, we can use the formula for exponential decay: V=P(1r)tV = P(1 - r)^t, where VV is the final value, PP is the initial value, rr is the rate of depreciation, and tt is the time in years.
  2. Identify Values: Let's identify the values of PP, rr, and tt. The initial value of the car PP is $15,300\$15,300, the rate of depreciation rr is 14.25%14.25\% or 0.14250.1425 when converted to a decimal, and the time tt is 66 years.
  3. Substitute Values: Now we can substitute these values into the formula to calculate the car's value after 66 years: V=15300(10.1425)6V = 15300(1 - 0.1425)^6.
  4. Calculate Inside Parentheses: Calculate the value inside the parentheses first: 10.1425=0.85751 - 0.1425 = 0.8575.
  5. Raise to Power: Now raise 0.85750.8575 to the power of 66: (0.8575)60.4088(0.8575)^6 \approx 0.4088 (rounded to four decimal places for precision in intermediate steps).
  6. Multiply Initial Value: Multiply the initial value of the car by the result from the previous step: V=15300×0.40886254.64V = 15300 \times 0.4088 \approx 6254.64.
  7. Round Final Value: Round the final value to the nearest cent: The value of the car after 66 years is approximately $6,254.64\$6,254.64.

More problems from Exponential growth and decay: word problems