Find all vertical asymptotes of the following function. f(x)=(2x+10)/(x^(2)-16)

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Identify Vertical Asymptotes: To find the vertical asymptotes of the function, we need to determine where the denominator is equal to zero, because vertical asymptotes occur at values of x that make the denominator undefined.Set Denominator Equal to Zero: Set the denominator equal to zero and solve for x: x^2 - 16 = 0.Factor Quadratic Equation: Factor the quadratic equation: (x - 4)(x + 4) = 0.Find Values of x: Find the values of x that make the equation true: x - 4 = 0 or x + 4 = 0.Solve Equations for x: Solve each equation for x: x = 4 and x = -4.Check Numerator for Zero: Check if these values of x also make the numerator zero, because if they do, they might be holes instead of vertical asymptotes. The numerator is 2x + 10, so we plug in x = 4 and x = -4 to see if it equals zero.Numerator for x = 4: For x = 4, the numerator is 2(4) + 10 = 8 + 10 = 18, which is not equal to zero.Numerator for x = -4: For x = -4, the numerator is 2(-4) + 10 = -8 + 10 = 2, which is also not equal to zero.Confirm Vertical Asymptotes: Since neither x = 4 nor x = -4 make the numerator zero, they are indeed vertical asymptotes of the function f(x).

Find all vertical asymptotes of the following function. $\newline$ $f(x)=\frac{2 x+10}{x^{2}-16}$

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Find all vertical asymptotes of the following function.\newlinef(x)=2x+10x2−16f(x)=\frac{2 x+10}{x^{2}-16}f(x)=x2−162x+10​

Find all vertical asymptotes of the following function. $\newline$ $f(x)=\frac{2 x+10}{x^{2}-16}$