Welcome to Bytelearn!

Let’s check out your problem:

A company claims that the mean monthly residential electricity consumption in a certain region is more than $860 \mathrm{kiloWatt-hours} \mathrm{(kWh).}$ You want to test this claim. You find that a random sample of $65$ residential customers has a mean monthly consumption of $890 \mathrm{kWh}$. Assume the population standard deviation is $128 \mathrm{kWh}$. At $\alpha=0.01$, can you support the claim? Complete parts (a) through ( $0$ ).$\newline$(a) Identify $\mathrm{H}_{0}$ and $\mathrm{H}_{\mathrm{a}}$. Choose the correct answer below.$\newline$A. $$\begin{array}{l} H_{0}: \mu>860 \text { (claim) } \\ H_{8}: \mu \leq 860 \end{array}$$$\newline$B. $$\begin{array}{l} H_{0}: \mu>890 \text { (claim) } \\ H_{a}: \mu \leq 890 \end{array}$$$\newline$c. $$\begin{array}{l} H_{0}: \mu \leq 890 \\ H_{2}: \mu>890 \text { (claim) } \end{array}$$$\newline$D. $$\begin{array}{l} H_{0}: \mu=860 \text { (claim) } \\ H_{a}: \mu \neq 860 \end{array}$$$\newline$E. $$\begin{array}{l} H_{0}: \mu=890 \\ H_{8}: \mu \neq 890 \text { (daim) } \end{array}$$$\newline$F. $$\begin{array}{l} H_{0}: \mu \leq 860 \\ H_{a}: \mu>860 \text { (claim) } \end{array}$$