Q. Point H is located at (2,−7). Select all of the following that are 7 units from point H. Choose all answers that apply:A x-axisB (−5,−7)C (−7,7)
Distance Formula Application: To find points that are 7 units away from point H(2,−7), we need to consider the distance formula, which is d=(x2−x1)2+(y2−y1)2, where d is the distance between two points (x1,y1) and (x2,y2). We are looking for points where d=7.
Check Option A: Let's first consider option A, the x-axis. The x-axis has the equation y=0. To find the distance from point H to the x-axis, we only need to consider the y-coordinate of H, which is −7. The distance from H to the x-axis is therefore x0 units, since the x-coordinate does not affect the vertical distance to the x-axis.
Check Option B: Now let's check option B, the point (−5,−7). We use the distance formula: d=(2−(−5))2+(−7−(−7))2. Simplifying, we get d=(2+5)2+02, which is d=72. This simplifies to d=7. So, point (−5,−7) is 7 units away from point H.
Check Option C: Finally, let's check option C, the point (−7,7). Again, we use the distance formula: d=(2−(−7))2+(−7−7)2. Simplifying, we get d=(2+7)2+(−7−7)2, which is d=92+(−14)2. This simplifies to d=81+196, which is d=277. The value of 277 is not 7, so point (−7,7) is not 7 units away from point d=(2−(−7))2+(−7−7)20.