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Patty is ordering vests for her scout troop to wear in the Veterans Day parade. She ordered 1212 vests from the Festive Features clothing shop. Since this was a bulk order, Festive Features reduced the price of each vest by 66 $\$. The total came to 132132 $\$. Which equation can you use to find the amount, vv, Festive Features normally charges for a vest?\newlineChoices:\newline(A) 6v12=1326v - 12 = 132\newline(B) 12(v6)=13212(v - 6) = 132\newline(C) 12v6=13212v - 6 = 132\newline(D) 6(v12)=1326(v - 12) = 132\newlineHow much does Festive Features normally charge for a vest?\newline____ $\$

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Q. Patty is ordering vests for her scout troop to wear in the Veterans Day parade. She ordered 1212 vests from the Festive Features clothing shop. Since this was a bulk order, Festive Features reduced the price of each vest by 66 $\$. The total came to 132132 $\$. Which equation can you use to find the amount, vv, Festive Features normally charges for a vest?\newlineChoices:\newline(A) 6v12=1326v - 12 = 132\newline(B) 12(v6)=13212(v - 6) = 132\newline(C) 12v6=13212v - 6 = 132\newline(D) 6(v12)=1326(v - 12) = 132\newlineHow much does Festive Features normally charge for a vest?\newline____ $\$
  1. Understand the problem: Understand the problem.\newlinePatty ordered 1212 vests and got a discount of $6\$6 per vest. The total cost was $132\$132. We need to find the original price of each vest before the discount.
  2. Set up the equation: Set up the equation.\newlineLet vv be the original price of one vest. The discount is $6\$6, so the price after the discount is v6v - 6. Patty ordered 1212 vests, so the total cost after the discount is 1212 times the discounted price of one vest, which equals $132\$132.\newlineThe equation is 12(v6)=13212(v - 6) = 132.
  3. Choose the correct equation: Choose the correct equation from the choices.\newlineThe correct equation that represents the situation is:\newline(B) 12(v6)=13212(v - 6) = 132
  4. Solve the equation for v: Solve the equation for v.\newline12(v6)=13212(v - 6) = 132\newlineDivide both sides by 1212 to isolate (v6)(v - 6):\newlinev6=13212v - 6 = \frac{132}{12}\newlinev6=11v - 6 = 11\newlineNow, add 66 to both sides to solve for v:\newlinev=11+6v = 11 + 6\newlinev=17v = 17
  5. Verify the solution: Verify the solution.\newlinePlug the value of vv back into the equation to check if it satisfies the equation:\newline12(176)=13212(17 - 6) = 132\newline12(11)=13212(11) = 132\newline132=132132 = 132\newlineThe solution v=17v = 17 satisfies the equation, so there is no math error.