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Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.
Based on this data, what is a reasonable estimate of the probability that the next pizza made is not a cheese pizza? Choose the best answer. Choose 1 answer:
(A)
51%
(B)
66%
(C)
71%
(D)
81%

Pat's Pizza made $21$ cheese pizzas, $14$ veggie pizzas, $23$ pepperoni pizzas, and $14$ sausage pizzas yesterday. $\newline$ Based on this data, what is a reasonable estimate of the probability that the next pizza made is not a cheese pizza? Choose the best answer. Choose $1$ answer: $\newline$ (A) $51\%$ $\newline$ (B) $66\%$ $\newline$ (C) $71\%$ $\newline$ (D) $81\%$

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Experimental probability

Full solution

Q. Pat's Pizza made

21

cheese pizzas,

14

veggie pizzas,

23

pepperoni pizzas, and

14

sausage pizzas yesterday.

\newline

Based on this data, what is a reasonable estimate of the probability that the next pizza made is not a cheese pizza? Choose the best answer. Choose

1

answer:

\newline

(A)

51\%

\newline

(B)

66\%

\newline

(C)

71\%

\newline

(D)

81\%

Calculate total number of pizzas: Calculate the total number of pizzas made. $\newline$ Total number of pizzas $=$ Number of cheese pizzas $+$ Number of veggie pizzas $+$ Number of pepperoni pizzas $+$ Number of sausage pizzas $\newline$ $= 21$ cheese pizzas $+ 14$ veggie pizzas $+ 23$ pepperoni pizzas $+ 14$ sausage pizzas $\newline$ $= 21 + 14 + 23 + 14$ $\newline$ $= 72$ pizzas
Calculate non-cheese pizzas: Calculate the number of pizzas that are not cheese pizzas. $\newline$ Number of non-cheese pizzas $=$ Total number of pizzas $-$ Number of cheese pizzas $\newline$ $= 72 - 21$ $\newline$ $= 51$ non-cheese pizzas
Calculate probability: Calculate the probability that the next pizza made is not a cheese pizza. $\newline$ Probability (not cheese pizza) = $\frac{\text{Number of non-cheese pizzas}}{\text{Total number of pizzas}}$ $\newline$ = $\frac{51}{72}$
Convert to percentage: Convert the probability to a percentage. $\newline$ Probability (not cheese pizza) as a percentage = $(\frac{51}{72}) \times 100\%$ $\newline$ $\approx 70.83\%$
Choose best estimate: Choose the best answer that is a reasonable estimate of the probability. Looking at the options, the closest estimate to $70.83\%$ is: (C) $71\%$

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