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Painted Pots lets customers choose and paint their own pottery. The store has teapots in multiple sizes. Rebecca chose to paint the largest teapot offered, which cost 18$18\$. She also painted 44 small teacups to go with her teapot. Rebecca spent a total of 42$42\$ on pottery.\newlineWhich equation can you use to find cc, the cost of each teacup?\newlineChoices:\newline(A) 4c+18=424c + 18 = 42\newline(B) 18c+4=4218c + 4 = 42\newline(C) 4(c+18)=424(c + 18) = 42\newline(D) 18(c+4)=4218(c + 4) = 42\newlineWhat was the cost of each teacup?\newline___$\_\_\_\$

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Q. Painted Pots lets customers choose and paint their own pottery. The store has teapots in multiple sizes. Rebecca chose to paint the largest teapot offered, which cost 18$18\$. She also painted 44 small teacups to go with her teapot. Rebecca spent a total of 42$42\$ on pottery.\newlineWhich equation can you use to find cc, the cost of each teacup?\newlineChoices:\newline(A) 4c+18=424c + 18 = 42\newline(B) 18c+4=4218c + 4 = 42\newline(C) 4(c+18)=424(c + 18) = 42\newline(D) 18(c+4)=4218(c + 4) = 42\newlineWhat was the cost of each teacup?\newline___$\_\_\_\$
  1. Identify Total Cost: Identify the total cost Rebecca spent on pottery.\newlineRebecca spent a total of 4242 (\$) on pottery.
  2. Cost of Largest Teapot: Identify the cost of the largest teapot.\(\newline\)The largest teapot cost Rebecca \(18\) \(\$\).
  3. Total Cost of Teacups: Determine the total cost of the teacups.\(\newline\)Since the total cost is \(42 (\$)\) and the teapot cost \(18 (\$)\), the cost of the teacups is \(42 (\$) - 18 (\$) = 24 (\$)\).
  4. Equation for Teacup Cost: Set up an equation to represent the cost of each teacup.\(\newline\)Rebecca painted \(4\) small teacups. Let \(c\) represent the cost of each teacup. The total cost of the teacups is \(4\) times the cost of one teacup, which is \(4c\). So, the equation is \(4c + 18 = 42\).
  5. Solve for c: Solve the equation for c.\(\newline\)Subtract \(18\) from both sides of the equation to isolate the term with \(c\).\(\newline\)\(4c + 18 - 18 = 42 - 18\)\(\newline\)\(4c = 24\)\(\newline\)Now, divide both sides by \(4\) to solve for \(c\).\(\newline\)\(\frac{4c}{4} = \frac{24}{4}\)\(\newline\)\(c = 6\)