Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

p(t)=31(2)^(2t) The equation models p, the amount of bacteria in colony-forming units in a bacteria culture after t hours of growth. Which of the following statements is the best interpretation of the ordered pair (2,496) ? Choose 1 answer: (A) There are 496 colony-forming units in the bacteria culture after 2 hours of growth. (B) There are 496 colony-forming units in the bacteria culture after 2 days of growth. (C) The number of colony-forming units in the bacteria culture reaches 496 after 2 generations. (D) The number of colony-forming units in the bacteria culture doubles every 496 minutes.

p(t)=31(2)2t p(t)=31(2)^{2 t} \newlineThe equation models p p , the amount of bacteria in colony-forming units in a bacteria culture after t t hours of growth. Which of the following statements is the best interpretation of the ordered pair (2,496) (2,496) ?\newlineChoose 11 answer:\newline(A) There are 496496 colony-forming units in the bacteria culture after 22 hours of growth.\newline(B) There are 496496 colony-forming units in the bacteria culture after 22 days of growth.\newline(C) The number of colony-forming units in the bacteria culture reaches 496496 after 22 generations.\newline(D) The number of colony-forming units in the bacteria culture doubles every 496496 minutes.

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Solve quadratic equations: word problemsright chevron icon

Full solution

Q. p(t)=31(2)2t p(t)=31(2)^{2 t} \newlineThe equation models p p , the amount of bacteria in colony-forming units in a bacteria culture after t t hours of growth. Which of the following statements is the best interpretation of the ordered pair (2,496) (2,496) ?\newlineChoose 11 answer:\newline(A) There are 496496 colony-forming units in the bacteria culture after 22 hours of growth.\newline(B) There are 496496 colony-forming units in the bacteria culture after 22 days of growth.\newline(C) The number of colony-forming units in the bacteria culture reaches 496496 after 22 generations.\newline(D) The number of colony-forming units in the bacteria culture doubles every 496496 minutes.
  1. Plug in t=2t=2: Plug in t=2t=2 into the equation to check if p(2)p(2) equals 496496.
    p(2)=31(2)(2∗2)p(2)=31(2)^{(2*2)}
    p(2)=31(2)4p(2)=31(2)^4
    p(2)=31∗16p(2)=31*16
    p(2)=496p(2)=496
  2. Calculate p(2)p(2): Since p(2)=496p(2) = 496, the ordered pair (2,496)(2,496) means there are 496496 colony-forming units after 22 hours of growth.

More problems from Solve quadratic equations: word problems

Question
Solve for v v .\newlinev2+8v+12=0 v^2+8v+12=0\newlineWrite each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.\newlinev= v=_____
Get tutor helpright-arrow

Posted 3 months ago

Question
Solve for u u .\newlineu2=9 u^2 = 9 \newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlineu= u = _____ or u= u = _____
Get tutor helpright-arrow

Posted 9 months ago

Question
Complete the square. Fill in the number that makes the polynomial a perfect-square quadratic.\newlinek2−20k+_____k^2 - 20k + \_\_\_\_\_
Get tutor helpright-arrow

Posted 8 months ago

Question
Solve by completing the square.\newlineu2−24u−23=0u^2 - 24u - 23 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newline`u` = ________ or `u` =______
Get tutor helpright-arrow

Posted 5 months ago

Question
Find the discriminant. \newline2q2−9q+8=02q^2 - 9q + 8 = 0\newline______
Get tutor helpright-arrow

Posted 5 months ago

Question
Solve the system of equations.\newliney=22x−38 y = 22x - 38 \newliney=x2+11x−14 y = x^2 + 11x - 14 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_) (\_,\_) \newline(_,_) (\_,\_)
Get tutor helpright-arrow

Posted 5 months ago

Question
Solve for aa.\newline(a+5)(a+1)=0(a + 5)(a + 1) = 0\newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlinea=a = _____ or a=a = _____
Get tutor helpright-arrow

Posted 8 months ago

Question
Let p=x2−7 p=x^{2}-7 . Which equation is equivalent to (x2−7)2−4x2+28=5 (x^{2}-7)^{2}-4x^{2}+28=5 in terms of p p ? Choose 11 answer: \newline(A) p2−4p+23=0 p^{2}-4p+23=0 \newline(B) p2+4p−5=0 p^{2}+4p-5=0 \newline(C) p2−4p−5=0 p^{2}-4p-5=0 \newline(D) p2+4p+23=0 p^{2}+4p+23=0
Get tutor helpright-arrow

Posted 8 months ago

Question
Let m=2x+3m=2x+3. Which equation is equivalent to (2x+3)2−14x−21=−6(2x+3)^{2}-14x-21=-6 in terms of mm? Choose 11 answer: \newline(A) m2+7m+6=0m^{2}+7m+6=0 \newline(B) m2−7m−15=0m^{2}-7m-15=0 \newline(C) m2−7m+6=0m^{2}-7m+6=0 \newline(D) m2+7m−15=0m^{2}+7m-15=0
Get tutor helpright-arrow

Posted 8 months ago

Question
Let m=x2+3m=x^{2}+3. Which equation is equivalent to (x2+3)2+7x2+21=−10(x^{2}+3)^{2}+7x^{2}+21=-10 in terms of mm? Choose 11 answer:\newline(A) m2−7m+31=0m^{2}-7m+31=0\newline(B) m2+7m+31=0m^{2}+7m+31=0\newline(C) m2−7m+10=0m^{2}-7m+10=0\newline(D) m2+7m+10=0m^{2}+7m+10=0
Get tutor helpright-arrow

Posted 9 months ago

View all (43)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant