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Let’s check out your problem:
Order the following values from least to greatest.
\newline
∣
9
∣
0
−
6
1
2
∣
−
1
∣
|9| \quad 0 \quad-6 \frac{1}{2} \quad|-1|
∣9∣
0
−
6
2
1
∣
−
1∣
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Math Problems
Algebra 2
Absolute values of complex numbers
Full solution
Q.
Order the following values from least to greatest.
\newline
∣
9
∣
0
−
6
1
2
∣
−
1
∣
|9| \quad 0 \quad-6 \frac{1}{2} \quad|-1|
∣9∣
0
−
6
2
1
∣
−
1∣
Calculate Absolute Value:
Calculate the absolute value of
9
9
9
, which is
∣
9
∣
|9|
∣9∣
.
\newline
∣
9
∣
=
9
|9| = 9
∣9∣
=
9
Recognize Non-Negative Integer:
Recognize that
0
0
0
is already a non-negative integer and does not need any further calculation.
0
=
0
0 = 0
0
=
0
Calculate Value of Expression:
Calculate the value of
−
6
(
1
2
)
-6\left(\frac{1}{2}\right)
−
6
(
2
1
)
.
−
6
(
1
2
)
=
−
6
×
0.5
=
−
3
-6\left(\frac{1}{2}\right) = -6 \times 0.5 = -3
−
6
(
2
1
)
=
−
6
×
0.5
=
−
3
Calculate Absolute Value:
Calculate the absolute value of
−
1
-1
−
1
, which is
∣
−
1
∣
|-1|
∣
−
1∣
.
\newline
∣
−
1
∣
=
1
|-1| = 1
∣
−
1∣
=
1
Order Values:
Now we have the values:
9
9
9
,
0
0
0
,
−
3
-3
−
3
, and
1
1
1
. We need to order them from least to greatest.
\newline
The order is
−
3
-3
−
3
,
0
0
0
,
1
1
1
,
9
9
9
.
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Question
3
⋅
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⋅
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i
)
=
\newline
Your answer should be a complex number in the form
a
+
b
i
a+b i
a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
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Question
(
35
−
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i
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(
13
+
25
i
)
=
(35-23 i)+(13+25 i)=
(
35
−
23
i
)
+
(
13
+
25
i
)
=
\newline
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(
a
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b
i
)
(a+b i)
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