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Nakeisha just started a running plan where she runs 7 miles the first week and then increases the number of miles she runs by 
10% each week. If she keeps up this plan for 25 weeks, how many total miles would Nakeisha have run, to the nearest whole number?
Answer:

Nakeisha just started a running plan where she runs 77 miles the first week and then increases the number of miles she runs by 10% 10 \% each week. If she keeps up this plan for 2525 weeks, how many total miles would Nakeisha have run, to the nearest whole number?\newlineAnswer:

Full solution

Q. Nakeisha just started a running plan where she runs 77 miles the first week and then increases the number of miles she runs by 10% 10 \% each week. If she keeps up this plan for 2525 weeks, how many total miles would Nakeisha have run, to the nearest whole number?\newlineAnswer:
  1. Identify initial amount and rate: Identify the initial amount of miles and the rate of increase.\newlineNakeisha starts with 77 miles in the first week and increases her running distance by 10%10\% each week.\newlineInitial miles (a)=7(a) = 7\newlineRate of increase (r)=10%(r) = 10\% or 0.100.10
  2. Calculate total miles per week: Calculate the total miles run for each week.\newlineThe total miles run in each subsequent week can be calculated using the formula for the nnth term of a geometric sequence:\newlineWeek nn miles = a×(1+r)(n1)a \times (1 + r)^{(n-1)}\newlineWe will use this formula to calculate the miles run each week and then sum them up for 2525 weeks.
  3. Calculate total miles over 2525 weeks: Calculate the total miles run over 2525 weeks.\newlineWe need to sum up the miles for each week from week 11 to week 2525.\newlineTotal miles = a+a(1+r)+a(1+r)2++a(1+r)251a + a(1+r) + a(1+r)^2 + \ldots + a(1+r)^{25-1}\newlineThis is the sum of a finite geometric series.
  4. Use formula for sum of series: Use the formula for the sum of a finite geometric series.\newlineThe sum SS of the first nn terms of a geometric series is given by:\newlineS=a×1(1+r)n1(1+r)S = a \times \frac{1 - (1 + r)^n}{1 - (1 + r)}\newlineWe will substitute n=25n = 25, a=7a = 7, and r=0.10r = 0.10 into this formula to find the total miles.
  5. Perform calculation using formula: Perform the calculation using the formula.\newlineS=7×(1(1+0.10)25)/(1(1+0.10))S = 7 \times (1 - (1 + 0.10)^{25}) / (1 - (1 + 0.10))\newlineS=7×(1(1.10)25)/(11.10)S = 7 \times (1 - (1.10)^{25}) / (1 - 1.10)\newlineS=7×(1(1.10)25)/(0.10)S = 7 \times (1 - (1.10)^{25}) / (-0.10)
  6. Calculate exact total and round: Calculate the exact total and then round to the nearest whole number.\newlineFirst, calculate (1.10)25(1.10)^{25}, then substitute it back into the formula to find SS.\newlineAfter finding SS, round it to the nearest whole number.
  7. Use calculator to find total: Use a calculator to find (1.10)25(1.10)^{25} and then find SS.(1.10)2510.834705...(1.10)^{25} \approx 10.834705...S7×(110.834705...)/(0.10)S \approx 7 \times (1 - 10.834705...) / (-0.10)S7×(9.834705...)/(0.10)S \approx 7 \times (-9.834705...) / (-0.10)S7×98.34705...S \approx 7 \times 98.34705...S688.42935...S \approx 688.42935...Rounded to the nearest whole number, S688S \approx 688 miles.

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