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n
=
4500
1
+
4500
(
0
,
0025
)
=
n=\frac{4500}{1+4500(0,0025)}=
n
=
1
+
4500
(
0
,
0025
)
4500
=
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Math Problems
Algebra 2
Evaluate logarithms using a calculator
Full solution
Q.
n
=
4500
1
+
4500
(
0
,
0025
)
=
n=\frac{4500}{1+4500(0,0025)}=
n
=
1
+
4500
(
0
,
0025
)
4500
=
Calculate Product:
First, we need to calculate the product of
4500
4500
4500
and
0.0025
0.0025
0.0025
.
\newline
Calculation:
4500
×
0.0025
=
11.25
4500 \times 0.0025 = 11.25
4500
×
0.0025
=
11.25
Add One:
Next, we add
1
1
1
to the product we just calculated.
\newline
Calculation:
1
+
11.25
=
12.25
1 + 11.25 = 12.25
1
+
11.25
=
12.25
Divide by Sum:
Now, we divide
4500
4500
4500
by the sum we found in the previous step.
\newline
Calculation:
4500
12.25
=
367.3469387755102
\frac{4500}{12.25} = 367.3469387755102
12.25
4500
=
367.3469387755102
Round Answer:
Finally, we round the answer to the nearest thousandth as the question does not specify the rounding precision.
\newline
Rounded answer:
367.347
367.347
367.347
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\newline
log
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Question
Which property of logarithms does this equation demonstrate?
\newline
log
3
3
+
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6
=
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lo
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\newline
Choices:
\newline
(A)
Product Property
\text{Product Property}
Product Property
\newline
(B)
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\text{Power Property}
Power Property
\newline
(C)
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\text{Quotient Property}
Quotient Property
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Question
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\newline
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\newline
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v
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(
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Question
Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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\newline
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Question
Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
Write your answer as a sum or difference of base-
6
6
6
logarithms or multiples of base-
6
6
6
logarithms. The inside of each logarithm must be a distinct constant or variable.
\newline
log
6
w
6
\log_6 w^6
lo
g
6
w
6
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