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Mr. Clarke plans to buy 33 security cameras to install outside his donut shop. He wants to spend less than $450\$450 on the cameras in all.\newlineLet xx represent how much Mr. Clarke wants to spend on each camera. Which inequality describes the problem?\newlineChoices:\newline(A) 3x4503x \leq 450\newline(B) 3x < 450\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMr. Clarke wants to spend less than $___\$\_\_\_ on each camera.

Full solution

Q. Mr. Clarke plans to buy 33 security cameras to install outside his donut shop. He wants to spend less than $450\$450 on the cameras in all.\newlineLet xx represent how much Mr. Clarke wants to spend on each camera. Which inequality describes the problem?\newlineChoices:\newline(A) 3x4503x \leq 450\newline(B) 3x<4503x < 450\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMr. Clarke wants to spend less than $___\$\_\_\_ on each camera.
  1. Define Inequality: Mr. Clarke wants to spend less than $450\$450 in total for 33 cameras. Let xx be the cost of one camera. The inequality to represent this situation is 3x < 450, because he wants to spend less than $450\$450 on all three cameras combined.
  2. Solve Inequality: To find the maximum amount Mr. Clarke can spend on each camera, solve the inequality 3x < 450. Divide both sides by 33 to isolate xx: \newline450÷3=150450 \div 3 = 150. So, x < 150.
  3. Final Solution: Mr. Clarke wants to spend less than $150\$150 on each camera. This is the solution to the inequality and answers the question prompt.

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