Mr. and Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 63%. If they have three children, what is the probability that exactly two of their three children will have that trait? Round your answer to the nearest thousandth.Answer:
Q. Mr. and Mrs. Doran have a genetic history such that the probability that a child being born to them with a certain trait is 63%. If they have three children, what is the probability that exactly two of their three children will have that trait? Round your answer to the nearest thousandth.Answer:
Use Binomial Probability Formula: Use the binomial probability formula: P(X=k)=C(n,k)⋅(p)k⋅(1−p)(n−k)Identify the values of n, k, and p. n=3 (the number of children) k=2 (the number of children with the trait) p=0.63 (the probability of a child having the trait)
Identify Values: Substitute the values into the binomial probability formula.P(X=2)=C(3,2)×(0.63)2×(1−0.63)3−2
Calculate Binomial Coefficient: Calculate the binomial coefficient C(3,2).C(3,2)=2!(3−2)!3!=13=3