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Mary plans to buy 55 tickets to go to an orchestra concert with her friends. She expects to spend at least $90\$90 on the tickets.\newlineLet xx represent how much Mary expects each ticket to cost. Which inequality describes the problem?\newlineChoices:\newline(A) 5x < 90\newline(B) 5x≥905x \geq 90\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMary expects each ticket to cost at least $_\$\_.

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Q. Mary plans to buy 55 tickets to go to an orchestra concert with her friends. She expects to spend at least $90\$90 on the tickets.\newlineLet xx represent how much Mary expects each ticket to cost. Which inequality describes the problem?\newlineChoices:\newline(A) 5x<905x < 90\newline(B) 5x≥905x \geq 90\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMary expects each ticket to cost at least $_\$\_.
  1. Define xx as cost: Mary plans to buy 55 tickets and expects to spend at least $90\$90. Let xx be the cost per ticket. We need to find the inequality that fits this situation.
  2. Calculate total cost: Multiply the number of tickets 55 by the cost per ticket xx. This gives us 5x5x, which represents the total cost Mary expects to spend.
  3. Formulate inequality: Since Mary expects to spend at least $90\$90, the inequality should show that the total cost (5x)(5x) is at least 9090. So, the correct inequality is 5x≥905x \geq 90.
  4. Isolate variable xx: To find the minimum cost per ticket, solve the inequality 5x≥905x \geq 90. Divide both sides by 55 to isolate xx.
  5. Perform division: x≥905x \geq \frac{90}{5}. Calculate 9090 divided by 55.
  6. Final cost per ticket: x≥18x \geq 18. This means Mary expects each ticket to cost at least \(\(18\)).

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