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Mary plans to buy 55 tickets to go to an orchestra concert with her friends. She expects to spend at least $90\$90 on the tickets.\newlineLet xx represent how much Mary expects each ticket to cost. Which inequality describes the problem?\newlineChoices:\newline(A) 5x905x \geq 90\newline(B) 5x < 90\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMary expects each ticket to cost at least $_\$\_.

Full solution

Q. Mary plans to buy 55 tickets to go to an orchestra concert with her friends. She expects to spend at least $90\$90 on the tickets.\newlineLet xx represent how much Mary expects each ticket to cost. Which inequality describes the problem?\newlineChoices:\newline(A) 5x905x \geq 90\newline(B) 5x<905x < 90\newlineSolve the inequality. Then, complete the sentence to describe the solution.\newlineMary expects each ticket to cost at least $_\$\_.
  1. Understand Problem & Inequality: Step 11: Understand the problem and set up the inequality.\newlineMary plans to buy 55 tickets and expects to spend at least $90\$90. This means the total cost for 55 tickets should be no less than $90\$90. We represent the cost of each ticket by xx.\newlineThe inequality that describes this situation is 5x905x \geq 90.
  2. Identify Correct Choice: Step 22: Identify the correct inequality choice.\newlineFrom the choices given:\newline(A) 5x905x \geq 90\newline(B) 5x < 90\newlineChoice (A) correctly represents the situation where Mary expects to spend at least $90\$90 on 55 tickets.
  3. Solve the Inequality: Step 33: Solve the inequality.\newlineTo find the minimum cost per ticket, solve the inequality 5x905x \geq 90.\newlineDivide both sides by 55:\newlinex905x \geq \frac{90}{5}\newlinex18x \geq 18

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