Maddy is carrying a 5 liter jug of sports drink that weighs 7.5kg . She wants to know how many kilograms a 2 liter jug of sports drink would weigh (w). She assumes the relationship between volume and weight is proportional. What is the weight of the 2 liter jug?

Identify Given Information: Identify the given information and what is being asked. Maddy has a 5-liter jug of sports drink that weighs 7.5 kg. We need to find the weight of a 2-liter jug of sports drink, assuming the relationship between volume and weight is proportional.Set Up Proportion: Set up the proportion to find the weight of the 2-liter jug. Since the relationship between volume and weight is proportional, we can set up the following proportion: (Weight of 5-liter jug) / (Volume of 5-liter jug) = (Weight of 2-liter jug) / (Volume of 2-liter jug) 7.5 kg / 5 liters = w / 2 litersSolve for Unknown Weight: Solve for the unknown weight (w) of the 2-liter jug. Cross-multiply to solve for w: 7.5 kg * 2 liters = 5 liters * w 15 kg = 5 liters * wDivide to Isolate Weight: Divide both sides of the equation by 5 liters to isolate w. 15 kg / 5 liters = w w = 3 kg

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Maddy is carrying a $5\,\text{liter}$ jug of sports drink that weighs $7.5\,\text{kg}$ . She wants to know how many kilograms a $2\,\text{liter}$ jug of sports drink would weigh $(w)$ . She assumes the relationship between volume and weight is proportional. What is the weight of the $2\,\text{liter}$ jug?

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Q. Maddy is carrying a

5\,\text{liter}

jug of sports drink that weighs

7.5\,\text{kg}

. She wants to know how many kilograms a

2\,\text{liter}

jug of sports drink would weigh

(w)

. She assumes the relationship between volume and weight is proportional. What is the weight of the

2\,\text{liter}

jug?

Identify Given Information: Identify the given information and what is being asked. $\newline$ Maddy has a $5$ -liter jug of sports drink that weighs $7.5$ kg. We need to find the weight of a $2$ -liter jug of sports drink, assuming the relationship between volume and weight is proportional.
Set Up Proportion: Set up the proportion to find the weight of the $2$ -liter jug. $\newline$ Since the relationship between volume and weight is proportional, we can set up the following proportion: $\newline$ $\frac{\text{Weight of } 5\text{-liter jug}}{\text{Volume of } 5\text{-liter jug}} = \frac{\text{Weight of } 2\text{-liter jug}}{\text{Volume of } 2\text{-liter jug}}$ $\newline$ $\frac{7.5 \text{ kg}}{5 \text{ liters}} = \frac{w}{2 \text{ liters}}$
Solve for Unknown Weight: Solve for the unknown weight $w$ of the $2$ -liter jug. $\newline$ Cross-multiply to solve for $w$ : $\newline$ $7.5 \, \text{kg} \times 2 \, \text{liters} = 5 \, \text{liters} \times w$ $\newline$ $15 \, \text{kg} = 5 \, \text{liters} \times w$
Divide to Isolate Weight: Divide both sides of the equation by $5 \text{ liters}$ to isolate $w$ . $\newline$ $\frac{15 \text{ kg}}{5 \text{ liters}} = w$ $\newline$ $w = 3 \text{ kg}$