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log95+log98=\log_{9}5+\log_{9}8=

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Q. log95+log98=\log_{9}5+\log_{9}8=
  1. Identify Properties: Identify the properties of logarithms that can be used to combine the logarithms.\newlineWe can use the product rule of logarithms to combine log9(5)\log_9(5) and log9(8)\log_9(8) into a single logarithm. The product rule states that logb(m)+logb(n)=logb(mn)\log_b(m) + \log_b(n) = \log_b(m*n), where bb is the base of the logarithms.
  2. Apply Product Rule: Apply the product rule to combine the logarithms.\newlineUsing the product rule, we can write log9(5)+log9(8)\log_9(5) + \log_9(8) as log9(58)\log_9(5*8).
  3. Perform Multiplication: Perform the multiplication inside the logarithm.\newlineNow we calculate the product inside the logarithm: 5×8=405 \times 8 = 40.\newlineSo, log9(5)+log9(8)\log_9(5) + \log_9(8) becomes log9(40)\log_9(40).
  4. Check for Simplification: Check if the logarithm can be simplified further.\newlineSince 4040 is not a power of 99, and there are no obvious factors of 4040 that are powers of 99, we cannot simplify the logarithm further. Therefore, extlog9(40) ext{log}_9(40) is the final answer.

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