Set up equation: Step 1: Set up the equation. We have log_(6)x = log_(x)36. This means 6 raised to some power equals x, and x raised to some power equals 36.Convert to exponential form: Step 2: Convert the logarithmic equation to an exponential form. 6^a = x and x^b = 36, where a = log_(6)x and b = log_(x)36.Substitute and simplify: Step 3: Substitute x from the first equation into the second equation. (6^a)^b = 36 6^(ab) = 36Recognize 36 as power of 6: Step 4: Recognize that 36 can be written as a power of 6. 36 = 6^2Set exponents equal: Step 5: Set the exponents equal to each other since the bases are the same. ab = 2Solve for x: Step 6: Solve for x using the first equation. Since a = log_(6)x, we know 6^a = x. From ab = 2 and knowing b = log_(x)36, we can substitute b = 2/a into the equation. a*(2/a) = 2 2 = 2 a = 1

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Solve for $x$ $\newline$ $\log _{6} x=\log _{x} 36$

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Precalculus

Convert between exponential and logarithmic form

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Q. Solve for

x

\newline

\log _{6} x=\log _{x} 36

Set up equation: Step $1$ : Set up the equation. $\newline$ We have $\log_{6}x = \log_{x}36$ . This means $6$ raised to some power equals $x$ , and $x$ raised to some power equals $36$ .
Convert to exponential form: Step $2$ : Convert the logarithmic equation to an exponential form. $\newline$ $6^a = x$ and $x^b = 36$ , where $a = \log_{6}x$ and $b = \log_{x}36$ .
Substitute and simplify: Step $3$ : Substitute $x$ from the first equation into the second equation. $\newline$ $(6^a)^b = 36$ $\newline$ $6^{ab} = 36$
Recognize $36$ as power of $6$ : Step $4$ : Recognize that $36$ can be written as a power of $6$ . $\newline$ $36 = 6^2$
Set exponents equal: Step $5$ : Set the exponents equal to each other since the bases are the same. $a^b = 2$
Solve for $x$ : Step $6$ : Solve for $x$ using the first equation. $\newline$ Since $a = \log_{6}x$ , we know $6^a = x$ . $\newline$ From $ab = 2$ and knowing $b = \log_{x}36$ , we can substitute $b = \frac{2}{a}$ into the equation. $\newline$ $a*\left(\frac{2}{a}\right) = 2$ $\newline$ $2 = 2$ $\newline$ $a = 1$