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log_(4)(x+3)=2

log⁡4(x+3)=2 \log _{4}(x+3)=2

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Full solution

Q. log⁡4(x+3)=2 \log _{4}(x+3)=2
  1. Rewrite as Exponential Equation: We have the equation: log⁡4(x+3)=2\log_{4}(x+3) = 2 How can we rewrite this as an exponential equation? log⁡4(x+3)=2\log_{4}(x+3) = 2 can be written as 42=x+34^2 = x+3.
  2. Calculate 424^2: We have: 424^2\newlineCalculate the value of 424^2.\newline42=4×4=164^2 = 4 \times 4 = 16\newlineSo, the equation 42=x+34^2 = x+3 becomes 16=x+316 = x+3.
  3. Solve for x: The equation 16=x+316 = x+3\newlineSolve for x.\newlinex+3=16x + 3 = 16\newlinex=16−3x = 16 - 3\newlinex=13x = 13

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