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log_(16)4=

log164= \log _{16} 4=

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Q. log164= \log _{16} 4=
  1. Identify Base: In log164\log_{16}4, 1616 is the base.\newlineRewrite 44 as a power of 1616.\newlineSince 44 is not a direct power of 1616, we need to express both 44 and 1616 in terms of a common base that is a factor of both numbers. The common base that can be used here is 22, because 44 is 161600 and 1616 is 161622.\newline161633\newline161644
  2. Rewrite Numbers as Powers: Now that we have both numbers as powers of 22, we can rewrite the logarithm in terms of base 22. \newlinelog(24)22log_{(2^4)}2^2 becomes log(24)22log_{(2^4)}2^2.
  3. Convert to Base 22: Apply the logarithm power rule, which states that logb(ac)=clogb(a)\log_b(a^c) = c \cdot \log_b(a), to simplify the expression.log2422\log_{2^4}2^2 becomes 2log2422 \cdot \log_{2^4}2.
  4. Apply Logarithm Power Rule: Now, we can simplify the logarithm because the base of the logarithm 242^4 and the number inside the logarithm 22 have the same base.log242\log_{2^4}2 is asking "to what power do we raise 242^4 to get 22?" Since 242^4 is 1616 and we want to get 22, we need to raise 1616 to the power of 1/41/4.2200
  5. Simplify Logarithm: Multiply the result from Step 44 by the coefficient from Step 33.\newline2×(14)2 \times \left(\frac{1}{4}\right)\newline2×14=122 \times \frac{1}{4} = \frac{1}{2}

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