Line v has an equation of y=-5x+6. Line w includes the point (-1,-2) and is perpendicular to line v. What is the equation of line w ?

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Line  v has an equation of  y=-5x+6. Line  w includes the point  (-1,-2) and is perpendicular to line  v. What is the equation of line  w ?

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Determine slope of line v: Determine the slope of line v. The equation of line v is given by y = -5x + 6. The slope (m) of a line in the slope-intercept form y = mx + b is the coefficient of x. Therefore, the slope of line v is -5.Find slope of line w: Find the slope of line w. Since line w is perpendicular to line v, its slope will be the negative reciprocal of the slope of line v. The negative reciprocal of -5 is 1/5. Therefore, the slope of line w is 1/5.Use point-slope form: Use the point-slope form to find the equation of line w. The point-slope form of a line is given by (y - y1) = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We have the slope of line w as 1/5 and the point (-1, -2). Plugging these values into the point-slope form gives us: (y - (-2)) = 1/5(x - (-1))Simplify equation to slope-intercept form: Simplify the equation from the point-slope form to the slope-intercept form. Simplifying the equation from the previous step, we get: y + 2 = 1/5(x + 1) y + 2 = 1/5x + 1/5 Subtracting 2 from both sides to solve for y, we get: y = 1/5x + 1/5 - 10/5 y = 1/5x - 9/5

Line $v$ has an equation of $y=-5 x+6$ . Line $w$ includes the point $(-1,-2)$ and is perpendicular to line $v$ . What is the equation of line $w$ ?

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Line v v v has an equation of y=−5x+6 y=-5 x+6 y=−5x+6. Line w w w includes the point (−1,−2) (-1,-2) (−1,−2) and is perpendicular to line v v v. What is the equation of line w w w ?

Line $v$ has an equation of $y=-5 x+6$ . Line $w$ includes the point $(-1,-2)$ and is perpendicular to line $v$ . What is the equation of line $w$ ?