Line v has an equation of y=−5x+6. Line w includes the point (−1,−2) and is perpendicular to line v. What is the equation of line w?Write the equation in slope-intercept form.
Q. Line v has an equation of y=−5x+6. Line w includes the point (−1,−2) and is perpendicular to line v. What is the equation of line w?Write the equation in slope-intercept form.
Determine slope of line v: Determine the slope of line v.The equation of line v is given as y=−5x+6. The slope (m) of a line in the slope-intercept form y=mx+b is the coefficient of x. Therefore, the slope of line v is −5.
Find slope of line w: Find the slope of line w. Since line w is perpendicular to line v, its slope will be the negative reciprocal of the slope of line v. The negative reciprocal of −5 is 51. Therefore, the slope of line w is 51.
Use point-slope form: Use the point-slope form to find the equation of line w. We have the slope of line w (51) and a point that lies on it (−1,−2). The point-slope form of a line's equation is y−y1=m(x−x1), where m is the slope and (x1,y1) is the point on the line. Plugging in the values, we get y−(−2)=51(x−(−1)).
Simplify equation to slope-intercept form: Simplify the equation from the point-slope form to the slope-intercept form.Starting with y+2=51(x+1), we distribute the slope on the right side to get y+2=51x+51. Then, we subtract 2 from both sides to isolate y, resulting in y=51x+51−2.
Combine like terms: Combine like terms to get the final equation of line w. We need to combine 51−2. Since 2 is the same as 510, we have y=51x+51−510, which simplifies to y=51x−59. This is the equation of line w in slope-intercept form.
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