Line v has an equation of y = -2x + 5. Perpendicular to line v is line w, which passes through the point (6,-5). What is the equation of line w? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers. ______

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Line v has an equation of y = -2x + 5. Perpendicular to line v is line w, which passes through the point (6,-5). What is the equation of line w? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.   ______

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Determine slope of line v: Determine the slope of line v. The equation of line v is given as y = -2x + 5. The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. Comparing the given equation with the slope-intercept form, we find that the slope (m) of line v is -2.Find slope of line w: Find the slope of line w. Since line w is perpendicular to line v, its slope will be the negative reciprocal of the slope of line v. The negative reciprocal of -2 is 1/2. Therefore, the slope (m) of line w is 1/2.Use point-slope form: Use the point-slope form to find the equation of line w. We have the slope of line w (1/2) and a point through which it passes (6,-5). The point-slope form of a line's equation is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Plugging in the values, we get y - (-5) = 1/2(x - 6).Simplify to slope-intercept form: Simplify the equation to slope-intercept form. Starting with y + 5 = 1/2(x - 6), we distribute the slope on the right side to get y + 5 = 1/2x - 3. Then, we subtract 5 from both sides to isolate y, resulting in y = 1/2x - 3 - 5. Simplifying further, we get y = 1/2x - 8.

Line $v$ has an equation of $y = -2x + 5$ . Perpendicular to line $v$ is line $w$ , which passes through the point $(6,-5)$ . What is the equation of line $w$ ? $\newline$ Write the equation in slope-intercept form.

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Line vvv has an equation of y=−2x+5y = -2x + 5y=−2x+5. Perpendicular to line vvv is line www, which passes through the point (6,−5)(6,-5)(6,−5). What is the equation of line www? \newlineWrite the equation in slope-intercept form.

Line $v$ has an equation of $y = -2x + 5$ . Perpendicular to line $v$ is line $w$ , which passes through the point $(6,-5)$ . What is the equation of line $w$ ? $\newline$ Write the equation in slope-intercept form.