Line v has an equation of y=-(1)/(5)x+9. Line w includes the point (-10,1) and is parallel to line v. What is the equation of line w?

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Line  v has an equation of  y=-(1)/(5)x+9. Line  w includes the point  (-10,1) and is parallel to line  v. What is the equation of line w?

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Determine slope of line v: Determine the slope of line v. Line v has the equation y = -(1/5)x + 9. The slope of a line in the form y = mx + b is m, where m is the coefficient of x. The slope of line v is -1/5.Find slope of line w: Since line w is parallel to line v, it must have the same slope. The slope of line w is therefore also -1/5.Use point-slope form: Use the point-slope form to find the equation of line w. The point-slope form of a line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We have the point (-10, 1) and the slope -1/5.Substitute slope and point: Substitute the slope and the point into the point-slope form. Using the point (-10, 1) and the slope -1/5, the equation becomes: y - 1 = -1/5(x - (-10)) y - 1 = -1/5(x + 10)Simplify equation: Simplify the equation to get it into slope-intercept form, y = mx + b. y - 1 = -1/5x - 1/5(10) y - 1 = -1/5x - 2 y = -1/5x - 2 + 1 y = -1/5x - 1

Line $v$ has an equation of $y=-\frac{1}{5} x+9$ . Line $w$ includes the point $(-10,1)$ and is parallel to line $v$ . What is the equation of line w?

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Line $v$ has an equation of $y=-\frac{1}{5} x+9$ . Line $w$ includes the point $(-10,1)$ and is parallel to line $v$ . What is the equation of line w?