Line s has an equation of y = 8x + 7. Line t is perpendicular to line s and passes through (-8,-2). What is the equation of line t? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers. ______

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Line s has an equation of y = 8x + 7. Line t is perpendicular to line s and passes through (-8,-2). What is the equation of line t? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.   ______

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Determine slope of line s: Determine the slope of line s. The equation of line s is given by y = 8x + 7. The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. Comparing the given equation with the slope-intercept form, we find that the slope (m) of line s is 8.Find slope of line t: Find the slope of line t. Since line t is perpendicular to line s, its slope will be the negative reciprocal of the slope of line s. The negative reciprocal of 8 is -1/8.Use point-slope form: Use the point-slope form to find the equation of line t. The point-slope form of a line is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We know that line t passes through the point (-8, -2) and has a slope of -1/8. Plugging these values into the point-slope form, we get: y - (-2) = -1/8(x - (-8))Simplify equation of line t: Simplify the equation of line t. Now we simplify the equation from the previous step: y + 2 = -1/8(x + 8) y + 2 = -1/8x - 1 Subtract 2 from both sides to get the equation in slope-intercept form: y = -1/8x - 1 - 2 y = -1/8x - 3

Line $s$ has an equation of $y = 8x + 7$ . Line $t$ is perpendicular to line $s$ and passes through $(-8,-2)$ . What is the equation of line $t$ ? $\newline$ Write the equation in slope-intercept form.

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Line sss has an equation of y=8x+7y = 8x + 7y=8x+7. Line ttt is perpendicular to line sss and passes through (−8,−2)(-8,-2)(−8,−2). What is the equation of line ttt?\newlineWrite the equation in slope-intercept form.

Line $s$ has an equation of $y = 8x + 7$ . Line $t$ is perpendicular to line $s$ and passes through $(-8,-2)$ . What is the equation of line $t$ ? $\newline$ Write the equation in slope-intercept form.