Line r has an equation of y= 6 7 x+1. Line s includes the point (7, – 7) and is perpendicular to line r. What is the equation of line s? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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Find Perpendicular Slope: Line r's slope is 6/7. Since line s is perpendicular to r, its slope is the negative reciprocal of 6/7, which is -7/6.Calculate Y-Intercept: Using the point (7, -7) and the slope -7/6, plug into the equation y = mx + b to find b, the y-intercept of line s. -7 = (-7/6)*7 + bSimplify Equation: Simplify the equation: -7 = -49/6 + b.Solve for b: Add 49/6 to both sides to solve for b: b = -7 + 49/6.Convert to Fraction: Convert -7 to a fraction with a denominator of 6: -7 = -42/6.Add Fractions: Now add -42/6 to 49/6 to get b: b = -42/6 + 49/6.Final Equation: Simplify b: b = 7/6.The equation of line s in slope-intercept form is y = -7/6x + 7/6.

Line $r$ has an equation of $y= \frac{6}{7}x+1$ . Line $s$ includes the point $(7, -7)$ and is perpendicular to line $r$ . What is the equation of line $s$ ? Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

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